3(6b-7)-(b+3)=21b

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Solution for 3(6b-7)-(b+3)=21b equation: 



3(6b-7)-(b+3)=21b

We move all terms to the left:

3(6b-7)-(b+3)-(21b)=0

We add all the numbers together, and all the variables

-21b+3(6b-7)-(b+3)=0

We multiply parentheses

-21b+18b-(b+3)-21=0

We get rid of parentheses

-21b+18b-b-3-21=0

We add all the numbers together, and all the variables

-4b-24=0

We move all terms containing b to the left, all other terms to the right

-4b=24

b=24/-4

b=-6

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