(2/3)x+x+3=38

Solution for (2/3)x+x+3=38 equation:

(2/3)x+x+3=38

We move all terms to the left:

(2/3)x+x+3-(38)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+x+3-38=0

We add all the numbers together, and all the variables

x+(+2/3)x-35=0

We multiply parentheses

2x^2+x-35=0

a = 2; b = 1; c = -35;
Δ = b2-4ac
Δ = 12-4·2·(-35)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{281}}{2*2}=\frac{-1-\sqrt{281}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{281}}{2*2}=\frac{-1+\sqrt{281}}{4}
$