(2/3)x+2/5(49-x)=26

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Solution for (2/3)x+2/5(49-x)=26 equation: 



(2/3)x+2/5(49-x)=26

We move all terms to the left:

(2/3)x+2/5(49-x)-(26)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5(49-x)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+2/5(-1x+49)-26=0

We multiply parentheses

2x^2+2/5(-1x+49)-26=0

We multiply all the terms by the denominator


2x^2*5(-1x+49)-26*5(-1x+49)+2=0

Wy multiply elements

10x^3(--130x(-+2=0

We do not support expression: x^3(

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