5(x+1)+27=7x-2(x-9)

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Solution for 5(x+1)+27=7x-2(x-9) equation: 



5(x+1)+27=7x-2(x-9)

We move all terms to the left:

5(x+1)+27-(7x-2(x-9))=0

We multiply parentheses

5x-(7x-2(x-9))+5+27=0



We calculate terms in parentheses: -(7x-2(x-9)), so:

7x-2(x-9)

We multiply parentheses

7x-2x+18

We add all the numbers together, and all the variables

5x+18

Back to the equation:

-(5x+18)



We add all the numbers together, and all the variables

5x-(5x+18)+32=0

We get rid of parentheses

5x-5x-18+32=0

We add all the numbers together, and all the variables

14!=0

There is no solution for this equation

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