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(2/3)x+1/9=(1/3)x
We move all terms to the left:
(2/3)x+1/9-((1/3)x)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x-((+1/3)x)+1/9=0
We multiply parentheses
2x^2-((+1/3)x)+1/9=0
We calculate fractions
2x^2+()/3x)*9)+3x/3x)*9)=0
We can not solve this equation
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