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(2/3)m+1=(1/6)m-2
We move all terms to the left:
(2/3)m+1-((1/6)m-2)=0
Domain of the equation: 3)m!=0
m!=0/1
m!=0
m∈R
Domain of the equation: 6)m-2)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
(+2/3)m-((+1/6)m-2)+1=0
We multiply parentheses
2m^2-((+1/6)m-2)+1=0
We multiply all the terms by the denominator
2m^2*6)m-2)-((+1*6)m-2)+1=0
We add all the numbers together, and all the variables
2m^2*6)m-2)-(6m-2)+1=0
Wy multiply elements
12m^3=0
We do not support empression: m^3
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