(1/4)f-(2/5)=2f-(1/3)

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Solution for (1/4)f-(2/5)=2f-(1/3) equation: 



(1/4)f-(2/5)=2f-(1/3)

We move all terms to the left:

(1/4)f-(2/5)-(2f-(1/3))=0



Domain of the equation: 4)f!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

(+1/4)f-(2f-(+1/3))-(+2/5)=0

We multiply parentheses

f^2-(2f-(+1/3))-(+2/5)=0

We get rid of parentheses

f^2-(2f-(+1/3))-2/5=0

We calculate fractions


f^2+(-(2f-(+1*5)/()+()/()=0



We calculate terms in parentheses: +(-(2f-(+1*5)/()+()/(), so:

-(2f-(+1*5)/()+()/(

We can not solve this equation

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