(2/3)*(1+n)=-(1/2)

Solution for (2/3)*(1+n)=-(1/2) equation:

(2/3)(1+n)=-(1/2)

We move all terms to the left:

(2/3)(1+n)-(-(1/2))=0


Domain of the equation: 3)(1+n)!=0

n∈R


We add all the numbers together, and all the variables

(+2/3)(n+1)-(-(+1/2))=0

We multiply parentheses ..

(+2n^2+2/3*1)-(-(+1/2))=0

We calculate fractions


2n^2/()+()/()=0

We add all the numbers together, and all the variables

2n^2/()+1=0

We multiply all the terms by the denominator


2n^2+1*()=0

We add all the numbers together, and all the variables

2n^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4}=0$