(2/(z+1))+(2/(z-1))=5/z+1

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Solution for (2/(z+1))+(2/(z-1))=5/z+1 equation: 



(2/(z+1))+(2/(z-1))=5/z+1

We move all terms to the left:

(2/(z+1))+(2/(z-1))-(5/z+1)=0



Domain of the equation: (z+1))!=0

z∈R





Domain of the equation: (z-1))!=0

z∈R





Domain of the equation: z+1)!=0

z∈R



We get rid of parentheses

(2/(z+1))+(2/(z-1))-5/z-1=0

We calculate fractions


((2*(z-1))*z)/((z+1))*(z-1))*z)+((2*(z+1))*z)/((z+1))*(z-1))*z)+(-5*(z+1))*z/((z+1))*(z-1))*z)-1=0

We can not solve this equation

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