(13x+20)=(10x+47)

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Solution for (13x+20)=(10x+47) equation: 



(13x+20)=(10x+47)

We move all terms to the left:

(13x+20)-((10x+47))=0

We get rid of parentheses

13x-((10x+47))+20=0



We calculate terms in parentheses: -((10x+47)), so:

(10x+47)

We get rid of parentheses

10x+47

Back to the equation:

-(10x+47)



We get rid of parentheses

13x-10x-47+20=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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