(2-x)+3(x+5)=10-4(6+2x)

Solution for (2-x)+3(x+5)=10-4(6+2x) equation:

(2-x)+3(x+5)=10-4(6+2x)

We move all terms to the left:

(2-x)+3(x+5)-(10-4(6+2x))=0

We add all the numbers together, and all the variables

(-1x+2)+3(x+5)-(10-4(2x+6))=0

We multiply parentheses

(-1x+2)+3x-(10-4(2x+6))+15=0

We get rid of parentheses

-1x+3x-(10-4(2x+6))+2+15=0


We calculate terms in parentheses: -(10-4(2x+6)), so:

10-4(2x+6)

determiningTheFunctionDomain
-4(2x+6)+10

We multiply parentheses

-8x-24+10

We add all the numbers together, and all the variables

-8x-14

Back to the equation:

-(-8x-14)


We add all the numbers together, and all the variables

2x-(-8x-14)+17=0

We get rid of parentheses

2x+8x+14+17=0

We add all the numbers together, and all the variables

10x+31=0

We move all terms containing x to the left, all other terms to the right

10x=-31

x=-31/10

x=-3+1/10