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x-13=1/3x+5
We move all terms to the left:
x-13-(1/3x+5)=0
Domain of the equation: 3x+5)!=0We get rid of parentheses
x∈R
x-1/3x-5-13=0
We multiply all the terms by the denominator
x*3x-5*3x-13*3x-1=0
Wy multiply elements
3x^2-15x-39x-1=0
We add all the numbers together, and all the variables
3x^2-54x-1=0
a = 3; b = -54; c = -1;
Δ = b2-4ac
Δ = -542-4·3·(-1)
Δ = 2928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2928}=\sqrt{16*183}=\sqrt{16}*\sqrt{183}=4\sqrt{183}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-4\sqrt{183}}{2*3}=\frac{54-4\sqrt{183}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+4\sqrt{183}}{2*3}=\frac{54+4\sqrt{183}}{6} $
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