(2-6x)(-4+3x)=0

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Solution for (2-6x)(-4+3x)=0 equation:



(2-6x)(-4+3x)=0
We add all the numbers together, and all the variables
(-6x+2)(3x-4)=0
We multiply parentheses ..
(-18x^2+24x+6x-8)=0
We get rid of parentheses
-18x^2+24x+6x-8=0
We add all the numbers together, and all the variables
-18x^2+30x-8=0
a = -18; b = 30; c = -8;
Δ = b2-4ac
Δ = 302-4·(-18)·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*-18}=\frac{-48}{-36} =1+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*-18}=\frac{-12}{-36} =1/3 $

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