11(k+4)-10=4(k-3)-24

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Solution for 11(k+4)-10=4(k-3)-24 equation: 



11(k+4)-10=4(k-3)-24

We move all terms to the left:

11(k+4)-10-(4(k-3)-24)=0

We multiply parentheses

11k-(4(k-3)-24)+44-10=0



We calculate terms in parentheses: -(4(k-3)-24), so:

4(k-3)-24

We multiply parentheses

4k-12-24

We add all the numbers together, and all the variables

4k-36

Back to the equation:

-(4k-36)



We add all the numbers together, and all the variables

11k-(4k-36)+34=0

We get rid of parentheses

11k-4k+36+34=0

We add all the numbers together, and all the variables

7k+70=0

We move all terms containing k to the left, all other terms to the right

7k=-70

k=-70/7

k=-10

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