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(2-5x)(2+5x)=5(1+2x)-(5x+2)(5x+2)-10x
We move all terms to the left:
(2-5x)(2+5x)-(5(1+2x)-(5x+2)(5x+2)-10x)=0
We add all the numbers together, and all the variables
(-5x+2)(5x+2)-(5(2x+1)-(5x+2)(5x+2)-10x)=0
We multiply parentheses ..
(-25x^2-10x+10x+4)-(5(2x+1)-(5x+2)(5x+2)-10x)=0
We calculate terms in parentheses: -(5(2x+1)-(5x+2)(5x+2)-10x), so:We get rid of parentheses
5(2x+1)-(5x+2)(5x+2)-10x
We add all the numbers together, and all the variables
-10x+5(2x+1)-(5x+2)(5x+2)
We multiply parentheses
-10x+10x-(5x+2)(5x+2)+5
We multiply parentheses ..
-(+25x^2+10x+10x+4)-10x+10x+5
We add all the numbers together, and all the variables
-(+25x^2+10x+10x+4)+5
We get rid of parentheses
-25x^2-10x-10x-4+5
We add all the numbers together, and all the variables
-25x^2-20x+1
Back to the equation:
-(-25x^2-20x+1)
-25x^2+25x^2-10x+10x+20x+4-1=0
We add all the numbers together, and all the variables
20x+3=0
We move all terms containing x to the left, all other terms to the right
20x=-3
x=-3/20
x=-3/20
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