6x-2(4-x)=40

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Solution for 6x-2(4-x)=40 equation: 



6x-2(4-x)=40

We move all terms to the left:

6x-2(4-x)-(40)=0

We add all the numbers together, and all the variables

6x-2(-1x+4)-40=0

We multiply parentheses

6x+2x-8-40=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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