(2-3i)(2-3i)=0

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Solution for (2-3i)(2-3i)=0 equation: 



(2-3i)(2-3i)=0

We add all the numbers together, and all the variables

(-3i+2)(-3i+2)=0

We multiply parentheses ..

(+9i^2-6i-6i+4)=0

We get rid of parentheses

9i^2-6i-6i+4=0

We add all the numbers together, and all the variables

9i^2-12i+4=0

a = 9; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·9·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{12}{18}=2/3$

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