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3(x-5)-5=2(-8x+8)-5x
We move all terms to the left:
3(x-5)-5-(2(-8x+8)-5x)=0
We multiply parentheses
3x-(2(-8x+8)-5x)-15-5=0
We calculate terms in parentheses: -(2(-8x+8)-5x), so:We add all the numbers together, and all the variables
2(-8x+8)-5x
We add all the numbers together, and all the variables
-5x+2(-8x+8)
We multiply parentheses
-5x-16x+16
We add all the numbers together, and all the variables
-21x+16
Back to the equation:
-(-21x+16)
3x-(-21x+16)-20=0
We get rid of parentheses
3x+21x-16-20=0
We add all the numbers together, and all the variables
24x-36=0
We move all terms containing x to the left, all other terms to the right
24x=36
x=36/24
x=1+1/2
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