(2+y)(3y+1)=0

Solution for (2+y)(3y+1)=0 equation:

(2+y)(3y+1)=0

We add all the numbers together, and all the variables

(y+2)(3y+1)=0

We multiply parentheses ..

(+3y^2+y+6y+2)=0

We get rid of parentheses

3y^2+y+6y+2=0

We add all the numbers together, and all the variables

3y^2+7y+2=0

a = 3; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·3·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*3}=\frac{-12}{6}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*3}=\frac{-2}{6}
=-1/3
$