-(1+1/6)x+(1+1/3)=-2x+8

Solution for -(1+1/6)x+(1+1/3)=-2x+8 equation:

-(1+1/6)x+(1+1/3)=-2x+8

We move all terms to the left:

-(1+1/6)x+(1+1/3)-(-2x+8)=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(1/6+1)x-(-2x+8)+(1/3+1)=0

We multiply parentheses

-x^2-x-(-2x+8)+(1/3+1)=0

We get rid of parentheses

-x^2-x+2x-8+1+1/3=0

We multiply all the terms by the denominator


-x^2*3-x*3+2x*3+1-8*3+1*3=0

We add all the numbers together, and all the variables

-x^2*3-x*3+2x*3-20=0

Wy multiply elements

-3x^2-3x+6x-20=0

We add all the numbers together, and all the variables

-3x^2+3x-20=0

a = -3; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·(-3)·(-20)
Δ = -231
Delta is less than zero, so there is no solution for the equation