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(2+x)/(x-2)=3
We move all terms to the left:
(2+x)/(x-2)-(3)=0
Domain of the equation: (x-2)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=2
x∈R
(x+2)/(x-2)-3=0
We multiply all the terms by the denominator
(x+2)-3*(x-2)=0
We multiply parentheses
(x+2)-3x+6=0
We get rid of parentheses
x-3x+2+6=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4
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