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6x+4+5x(x+6)=56
We move all terms to the left:
6x+4+5x(x+6)-(56)=0
We add all the numbers together, and all the variables
6x+5x(x+6)-52=0
We multiply parentheses
5x^2+6x+30x-52=0
We add all the numbers together, and all the variables
5x^2+36x-52=0
a = 5; b = 36; c = -52;
Δ = b2-4ac
Δ = 362-4·5·(-52)
Δ = 2336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2336}=\sqrt{16*146}=\sqrt{16}*\sqrt{146}=4\sqrt{146}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{146}}{2*5}=\frac{-36-4\sqrt{146}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{146}}{2*5}=\frac{-36+4\sqrt{146}}{10} $
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