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(2+2k)/3=3k-11
We move all terms to the left:
(2+2k)/3-(3k-11)=0
We add all the numbers together, and all the variables
(2k+2)/3-(3k-11)=0
We get rid of parentheses
(2k+2)/3-3k+11=0
We multiply all the terms by the denominator
(2k+2)-3k*3+11*3=0
We add all the numbers together, and all the variables
(2k+2)-3k*3+33=0
Wy multiply elements
(2k+2)-9k+33=0
We get rid of parentheses
2k-9k+2+33=0
We add all the numbers together, and all the variables
-7k+35=0
We move all terms containing k to the left, all other terms to the right
-7k=-35
k=-35/-7
k=+5
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