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2x(x+1)-3(x+3)=104
We move all terms to the left:
2x(x+1)-3(x+3)-(104)=0
We multiply parentheses
2x^2+2x-3x-9-104=0
We add all the numbers together, and all the variables
2x^2-1x-113=0
a = 2; b = -1; c = -113;
Δ = b2-4ac
Δ = -12-4·2·(-113)
Δ = 905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{905}}{2*2}=\frac{1-\sqrt{905}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{905}}{2*2}=\frac{1+\sqrt{905}}{4} $
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