(2)4a2=9

Solution for (2)4a2=9 equation:

(2)4a^2=9

We move all terms to the left:

(2)4a^2-(9)=0

a = 24; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·24·(-9)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*24}=\frac{0-12\sqrt{6}}{48}
=-\frac{12\sqrt{6}}{48}
=-\frac{\sqrt{6}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*24}=\frac{0+12\sqrt{6}}{48}
=\frac{12\sqrt{6}}{48}
=\frac{\sqrt{6}}{4}
$