64=8(8+4c)=32

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Solution for 64=8(8+4c)=32 equation: 



64=8(8+4c)=32

We move all terms to the left:

64-(8(8+4c))=0

We add all the numbers together, and all the variables

-(8(4c+8))+64=0



We calculate terms in parentheses: -(8(4c+8)), so:

8(4c+8)

We multiply parentheses

32c+64

Back to the equation:

-(32c+64)



We get rid of parentheses

-32c-64+64=0

We add all the numbers together, and all the variables

-32c=0

c=0/-32

c=0

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