(2)/(y-2)+1=(y)/(y+2)

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Solution for (2)/(y-2)+1=(y)/(y+2) equation: 



(2)/(y-2)+1=(y)/(y+2)

We move all terms to the left:

(2)/(y-2)+1-((y)/(y+2))=0



Domain of the equation: (y-2)!=0

We move all terms containing y to the left, all other terms to the right

y!=2

y∈R





Domain of the equation: (y+2))!=0

y∈R



We calculate fractions


2y/((y-2)*(y+2)))+(-(y*(y-2))/((y-2)*(y+2)))+1=0

We calculate fractions


(2y*((y-2)*(y+2)))+1)/(((y-2)*(y+2)))+(*((y-2)*(y+2)))+1)+(-(y*(y-2))*((y-2)*(y+2)))+()/(((y-2)*(y+2)))+(*((y-2)*(y+2)))+1)=0



We calculate terms in parentheses: +(2y*((y-2)*(y+2))), so:

2y*((y-2)*(y+2))



We can not solve this equation

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