(7y-4)+59+(3y-5)=180

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Solution for (7y-4)+59+(3y-5)=180 equation: 



(7y-4)+59+(3y-5)=180

We move all terms to the left:

(7y-4)+59+(3y-5)-(180)=0

We add all the numbers together, and all the variables

(7y-4)+(3y-5)-121=0

We get rid of parentheses

7y+3y-4-5-121=0

We add all the numbers together, and all the variables

10y-130=0

We move all terms containing y to the left, all other terms to the right

10y=130

y=130/10

y=13

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