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(2)/(x)=(2x+5)/(2x-3)
We move all terms to the left:
(2)/(x)-((2x+5)/(2x-3))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (2x-3))!=0We calculate fractions
x∈R
4x/(-1x^2)+(-((2x+5)*x)/(-1x^2)=0
We calculate terms in parentheses: +(-((2x+5)*x)/(-1x^2), so:We get rid of parentheses
-((2x+5)*x)/(-1x^2
We multiply all the terms by the denominator
-((2x+5)*x)
We calculate terms in parentheses: -((2x+5)*x), so:We get rid of parentheses
(2x+5)*x
We multiply parentheses
2x^2+5x
Back to the equation:
-(2x^2+5x)
-2x^2-5x
Back to the equation:
+(-2x^2-5x)
4x/(-1x^2)-2x^2-5x=0
We multiply all the terms by the denominator
-2x^2*(-1x^2)-5x*(-1x^2)+4x=0
We multiply parentheses
-2x^2*(-1x^2)+5x^3+4x=0
We do not support expression: x^3
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