6-4(2x+3)=3(x-1)+x

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Solution for 6-4(2x+3)=3(x-1)+x equation: 



6-4(2x+3)=3(x-1)+x

We move all terms to the left:

6-4(2x+3)-(3(x-1)+x)=0

We multiply parentheses

-8x-(3(x-1)+x)-12+6=0



We calculate terms in parentheses: -(3(x-1)+x), so:

3(x-1)+x

We add all the numbers together, and all the variables

x+3(x-1)

We multiply parentheses

x+3x-3

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

-8x-(4x-3)-6=0

We get rid of parentheses

-8x-4x+3-6=0

We add all the numbers together, and all the variables

-12x-3=0

We move all terms containing x to the left, all other terms to the right

-12x=3

x=3/-12

x=-1/4

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