(2)(0.25z)=(2)(z-5)

Solution for (2)(0.25z)=(2)(z-5) equation:

(2)(0.25z)=(2)(z-5)

We move all terms to the left:

(2)(0.25z)-((2)(z-5))=0

We add all the numbers together, and all the variables

2(+0.25z)-(2(z-5))=0

We multiply parentheses

0z-(2(z-5))=0


We calculate terms in parentheses: -(2(z-5)), so:

2(z-5)

We multiply parentheses

2z-10

Back to the equation:

-(2z-10)


We add all the numbers together, and all the variables

z-(2z-10)=0

We get rid of parentheses

z-2z+10=0

We add all the numbers together, and all the variables

-1z+10=0

We move all terms containing z to the left, all other terms to the right

-z=-10

z=-10/-1

z=+10