2(2x-3)+x=1/2(120x+6

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Solution for 2(2x-3)+x=1/2(120x+6 equation: 



2(2x-3)+x=1/2(120x+6

We move all terms to the left:

2(2x-3)+x-(1/2(120x+6)=0



Domain of the equation: 2(120x+6)!=0

x∈R



We add all the numbers together, and all the variables

x+2(2x-3)-(1/2(120x+6)=0

We multiply parentheses

x+4x-(1/2(120x+6)-6=0

We multiply all the terms by the denominator


x*2(120x+6)+4x*2(120x+6)-6-6-(1=0

We add all the numbers together, and all the variables

x*2(120x+6)+4x*2(120x+6)=0

Wy multiply elements

2x^2(1+8x^2(1=0

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