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(2(x-4))/5=-x+4
We move all terms to the left:
(2(x-4))/5-(-x+4)=0
We add all the numbers together, and all the variables
(2(x-4))/5-(-1x+4)=0
We get rid of parentheses
(2(x-4))/5+1x-4=0
We multiply all the terms by the denominator
(2(x-4))+1x*5-4*5=0
We calculate terms in parentheses: +(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
+(2x-8)
(2x-8)+1x*5-20=0
Wy multiply elements
(2x-8)+5x-20=0
We get rid of parentheses
2x+5x-8-20=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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