4(k+4)=38+2k

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Solution for 4(k+4)=38+2k equation: 



4(k+4)=38+2k

We move all terms to the left:

4(k+4)-(38+2k)=0

We add all the numbers together, and all the variables

4(k+4)-(2k+38)=0

We multiply parentheses

4k-(2k+38)+16=0

We get rid of parentheses

4k-2k-38+16=0

We add all the numbers together, and all the variables

2k-22=0

We move all terms containing k to the left, all other terms to the right

2k=22

k=22/2

k=11

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