(2(x-4))/3=3x+6

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Solution for (2(x-4))/3=3x+6 equation: 



(2(x-4))/3=3x+6

We move all terms to the left:

(2(x-4))/3-(3x+6)=0

We get rid of parentheses

(2(x-4))/3-3x-6=0

We multiply all the terms by the denominator


(2(x-4))-3x*3-6*3=0



We calculate terms in parentheses: +(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

+(2x-8)



We add all the numbers together, and all the variables

(2x-8)-3x*3-18=0

Wy multiply elements

(2x-8)-9x-18=0

We get rid of parentheses

2x-9x-8-18=0

We add all the numbers together, and all the variables

-7x-26=0

We move all terms containing x to the left, all other terms to the right

-7x=26

x=26/-7

x=-3+5/7

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