(2(x-3))/3=6+2x

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Solution for (2(x-3))/3=6+2x equation: 



(2(x-3))/3=6+2x

We move all terms to the left:

(2(x-3))/3-(6+2x)=0

We add all the numbers together, and all the variables

(2(x-3))/3-(2x+6)=0

We get rid of parentheses

(2(x-3))/3-2x-6=0

We multiply all the terms by the denominator


(2(x-3))-2x*3-6*3=0



We calculate terms in parentheses: +(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

+(2x-6)



We add all the numbers together, and all the variables

(2x-6)-2x*3-18=0

Wy multiply elements

(2x-6)-6x-18=0

We get rid of parentheses

2x-6x-6-18=0

We add all the numbers together, and all the variables

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6

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