(2(x+3))+(2(2x-6))=26

Solution for (2(x+3))+(2(2x-6))=26 equation:

(2(x+3))+(2(2x-6))=26

We move all terms to the left:

(2(x+3))+(2(2x-6))-(26)=0


We calculate terms in parentheses: +(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

+(2x+6)



We calculate terms in parentheses: +(2(2x-6)), so:

2(2x-6)

We multiply parentheses

4x-12

Back to the equation:

+(4x-12)


We get rid of parentheses

2x+4x+6-12-26=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3