7x-4+(6x+10)=45

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Solution for 7x-4+(6x+10)=45 equation: 



7x-4+(6x+10)=45

We move all terms to the left:

7x-4+(6x+10)-(45)=0

We add all the numbers together, and all the variables

7x+(6x+10)-49=0

We get rid of parentheses

7x+6x+10-49=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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