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(2(x+1))/5=4x-4
We move all terms to the left:
(2(x+1))/5-(4x-4)=0
We get rid of parentheses
(2(x+1))/5-4x+4=0
We multiply all the terms by the denominator
(2(x+1))-4x*5+4*5=0
We calculate terms in parentheses: +(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
+(2x+2)
(2x+2)-4x*5+20=0
Wy multiply elements
(2x+2)-20x+20=0
We get rid of parentheses
2x-20x+2+20=0
We add all the numbers together, and all the variables
-18x+22=0
We move all terms containing x to the left, all other terms to the right
-18x=-22
x=-22/-18
x=1+2/9
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