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5(2x+3)=4(2x+1)
We move all terms to the left:
5(2x+3)-(4(2x+1))=0
We multiply parentheses
10x-(4(2x+1))+15=0
We calculate terms in parentheses: -(4(2x+1)), so:We get rid of parentheses
4(2x+1)
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
10x-8x-4+15=0
We add all the numbers together, and all the variables
2x+11=0
We move all terms containing x to the left, all other terms to the right
2x=-11
x=-11/2
x=-5+1/2
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