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(2(x+1))/4=3x-2
We move all terms to the left:
(2(x+1))/4-(3x-2)=0
We get rid of parentheses
(2(x+1))/4-3x+2=0
We multiply all the terms by the denominator
(2(x+1))-3x*4+2*4=0
We calculate terms in parentheses: +(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
+(2x+2)
(2x+2)-3x*4+8=0
Wy multiply elements
(2x+2)-12x+8=0
We get rid of parentheses
2x-12x+2+8=0
We add all the numbers together, and all the variables
-10x+10=0
We move all terms containing x to the left, all other terms to the right
-10x=-10
x=-10/-10
x=1
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