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(2(2x+1))/3=10
We move all terms to the left:
(2(2x+1))/3-(10)=0
We multiply all the terms by the denominator
(2(2x+1))-10*3=0
We calculate terms in parentheses: +(2(2x+1)), so:We add all the numbers together, and all the variables
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
+(4x+2)
(4x+2)-30=0
We get rid of parentheses
4x+2-30=0
We add all the numbers together, and all the variables
4x-28=0
We move all terms containing x to the left, all other terms to the right
4x=28
x=28/4
x=7
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