1,2(3-x)-0,3(4x+1)=0,1-0,8(3x-4)

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Solution for 1,2(3-x)-0,3(4x+1)=0,1-0,8(3x-4) equation: 



1.2(3-x)-0.3(4x+1)=0.1-0.8(3x-4)

We move all terms to the left:

1.2(3-x)-0.3(4x+1)-(0.1-0.8(3x-4))=0

We add all the numbers together, and all the variables

1.2(-1x+3)-0.3(4x+1)-(0.1-0.8(3x-4))=0

We multiply parentheses

-1.2x-1.2x-(0.1-0.8(3x-4))+3.6-0.3=0



We calculate terms in parentheses: -(0.1-0.8(3x-4)), so:

0.1-0.8(3x-4)

determiningTheFunctionDomain
-0.8(3x-4)+0.1

We multiply parentheses

-2.4x+3.2+0.1

We add all the numbers together, and all the variables

-2.4x+3.3

Back to the equation:

-(-2.4x+3.3)



We add all the numbers together, and all the variables

-2.4x-(-2.4x+3.3)+3.3=0

We get rid of parentheses

-2.4x+2.4x-3.3+3.3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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