(2((x)6))+(3((1.5)x)+(4((x)6))+(2((2)x))=12.25

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Solution for (2((x)6))+(3((1.5)x)+(4((x)6))+(2((2)x))=12.25 equation: 



(2((x)6))+(3((1.5)x)+(4((x)6))+(2((2)x))=12.25

We move all terms to the left:

(2((x)6))+(3((1.5)x)+(4((x)6))+(2((2)x))-(12.25)=0

determiningTheFunctionDomain
(2x6)+(3((1.5)x)+(4x6)+(22x)-(12.25)=0

We add all the numbers together, and all the variables

(+2x^6)+(3((1.5)x)+(+4x^6)+(+22x)-(12.25)=0

We get rid of parentheses

2x^6+(3((1.5)x)+(+4x^6)+(+22x)-(12.25)=0



We calculate terms in parentheses: +(3((1.5)x)+(+4x^6)+(+22x)-(12.25), so:

3((1.5)x)+(+4x^6)+(+22x)-(12.25

We do not support expression: x^6

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