-5=3(b+2)-6b

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Solution for -5=3(b+2)-6b equation: 



-5=3(b+2)-6b

We move all terms to the left:

-5-(3(b+2)-6b)=0



We calculate terms in parentheses: -(3(b+2)-6b), so:

3(b+2)-6b

We add all the numbers together, and all the variables

-6b+3(b+2)

We multiply parentheses

-6b+3b+6

We add all the numbers together, and all the variables

-3b+6

Back to the equation:

-(-3b+6)



We get rid of parentheses

3b-6-5=0

We add all the numbers together, and all the variables

3b-11=0

We move all terms containing b to the left, all other terms to the right

3b=11

b=11/3

b=3+2/3

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