(1=9x-2)2=3x+2

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Solution for (1=9x-2)2=3x+2 equation: 



(1=9x-2)2=3x+2

We move all terms to the left:

(1-(9x-2)2)=0



We calculate terms in parentheses: +(1-(9x-2)2), so:

1-(9x-2)2

determiningTheFunctionDomain
-(9x-2)2+1

We multiply parentheses

-18x+4+1

We add all the numbers together, and all the variables

-18x+5

Back to the equation:

+(-18x+5)



We get rid of parentheses

-18x+5=0

We move all terms containing x to the left, all other terms to the right

-18x=-5

x=-5/-18

x=5/18

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