(180-(3x+10))+(2x+20)+40=180

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Solution for (180-(3x+10))+(2x+20)+40=180 equation: 



(180-(3x+10))+(2x+20)+40=180

We move all terms to the left:

(180-(3x+10))+(2x+20)+40-(180)=0

We add all the numbers together, and all the variables

(180-(3x+10))+(2x+20)-140=0

We get rid of parentheses

(180-(3x+10))+2x+20-140=0



We calculate terms in parentheses: +(180-(3x+10)), so:

180-(3x+10)

determiningTheFunctionDomain
-(3x+10)+180

We get rid of parentheses

-3x-10+180

We add all the numbers together, and all the variables

-3x+170

Back to the equation:

+(-3x+170)



We add all the numbers together, and all the variables

2x+(-3x+170)-120=0

We get rid of parentheses

2x-3x+170-120=0

We add all the numbers together, and all the variables

-1x+50=0

We move all terms containing x to the left, all other terms to the right

-x=-50

x=-50/-1

x=+50

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