1/4(20x-8)=3/4(8x+36)

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Solution for 1/4(20x-8)=3/4(8x+36) equation: 



1/4(20x-8)=3/4(8x+36)

We move all terms to the left:

1/4(20x-8)-(3/4(8x+36))=0



Domain of the equation: 4(20x-8)!=0

x∈R





Domain of the equation: 4(8x+36))!=0

x∈R



We calculate fractions


(4x8/(4(20x-8)*4(8x+36)))+(-12x2/(4(20x-8)*4(8x+36)))=0



We calculate terms in parentheses: +(4x8/(4(20x-8)*4(8x+36))), so:

4x8/(4(20x-8)*4(8x+36))

We multiply all the terms by the denominator


4x8

We add all the numbers together, and all the variables

4x^8

We do not support expression: x^8

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