(18-6)+(36+4x)=12-(4x-18)

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Solution for (18-6)+(36+4x)=12-(4x-18) equation:



(18-6)+(36+4x)=12-(4x-18)
We move all terms to the left:
(18-6)+(36+4x)-(12-(4x-18))=0
We add all the numbers together, and all the variables
(4x+36)-(12-(4x-18))+12=0
We get rid of parentheses
4x-(12-(4x-18))+36+12=0
We calculate terms in parentheses: -(12-(4x-18)), so:
12-(4x-18)
determiningTheFunctionDomain -(4x-18)+12
We get rid of parentheses
-4x+18+12
We add all the numbers together, and all the variables
-4x+30
Back to the equation:
-(-4x+30)
We add all the numbers together, and all the variables
4x-(-4x+30)+48=0
We get rid of parentheses
4x+4x-30+48=0
We add all the numbers together, and all the variables
8x+18=0
We move all terms containing x to the left, all other terms to the right
8x=-18
x=-18/8
x=-2+1/4

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