1/9y+1/4y=11/36

Solution for 1/9y+1/4y=11/36 equation:

1/9y+1/4y=11/36

We move all terms to the left:

1/9y+1/4y-(11/36)=0


Domain of the equation: 9y!=0

y!=0/9

y!=0

y∈R



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We add all the numbers together, and all the variables

1/9y+1/4y-(+11/36)=0

We get rid of parentheses

1/9y+1/4y-11/36=0

We calculate fractions


(-1584y^2)/3888y^2+432y/3888y^2+972y/3888y^2=0

We multiply all the terms by the denominator


(-1584y^2)+432y+972y=0

We add all the numbers together, and all the variables

(-1584y^2)+1404y=0

We get rid of parentheses

-1584y^2+1404y=0

a = -1584; b = 1404; c = 0;
Δ = b2-4ac
Δ = 14042-4·(-1584)·0
Δ = 1971216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1971216}=1404$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1404)-1404}{2*-1584}=\frac{-2808}{-3168}
=39/44
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1404)+1404}{2*-1584}=\frac{0}{-3168}
=0
$